So choose (0,0,1) as the new center of the interior and (0,0,0) as the single point of attachment. Just translate the ball up one unit. Then the equat...on of the exploded positron would be the union of x^ + y^2 + (1-z)^2 <, 1 with the line segment {(x,0,0) | 0 <,= x <,= 4pi}.’ ‘But wait. The line segment {(0,y,0) | 0 <,= y <,=4pi} would work equally well. In fact, for any fixed real number u and each v where 0 <,= v <,= 4pi the line segment {(v*sin(u),v*cos(u),0) | 0 <,= v <,=. Mujhe lga ki wo sabko bta degi par usne yeh baat kisi ko nai boli agle din phir wo subha aayi to main uske boobs dekh raha tha aur ek haant mera kachche main tha wo jaan buj kar aur dikhane lagi phir boli kya chachi aapko deti nai hai kya maine kaha nai wo abhi uska abhi treatment chal raha hai maine usse se kaha ki tum ek baar mujhe apne boobs dikha do to main apne aap ko shaant kar lunga wo kehne lagi ki roz to dekte ho shaanti nai milti usi samay main bed se utha aur uske pass ja kar use. More

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